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AIR OXYGEN AND COMBUSTION

A.THE ATMOSPHERE

 1. The atmosphere is made up of air. Air is a mixture of colourless, odorless gases which is felt as wind (air in motion).All living things breath in air for respiration. Plants use air for respiration and photosynthesis.

2. The main gases present in the atmosphere/air:

GasApproximate % composition by volume
Nitrogen78.0
Oxygen21.0
Carbon(IV)oxide0.03
Noble gases1.0
Water vapourVary from region

3. The following experiments below shows the presence and composition of the gases in air/atmosphere

(a)To find the composition of air supporting combustion using a candle stick

Procedure

Measure the length of an empty gas jar M1. Place a candle stick on a Petri dish. Float it on water in basin/trough. Cover it with the gas jar. Mark the level of the water in the gas jar M2. Remove the gas jar. Light the candle sick. Carefully cover it with the gas jar. Observe for two minutes. Mark the new level of the water M3.

Set up of apparatus

Sample observations

Candle continues to burn then extinguished/goes off

Level of water in the gas jar rises after igniting the candle

Length of empty gas jar = M1= 14cm

Length of gas jar without water before igniting candle = M2= 10 cm

Length of gas jar with water before igniting candle = M1 – M2= 14- 10 = 4 cm

Length of gas jar with water after igniting candle = M3 = 8 cm

Length of gas jar without water after igniting candle = M1 – M3 = 10 -8 = 2 cm

Explanation

Candle burns in air. In a closed system (vessel), the candle continues to burn using the part of air that support burning/combustion. This is called the active part of air. The candle goes off/extinguished when all theactive part of air is used up. The level of the water rises to occupy the space /volume occupied by the usedactive part of air.

The experiment is better when very dilute sodium/potassium hydroxide is used instead of water. Dilute Potassium/ sodium hydroxide absorb Carbon (IV) oxide gas that comes out from burning/combustion of candle stick.

From the experiment above the % composition of the:

 (i) Active part of air can be calculated:

M2 – M3 x 100%   =>     10- 8 x 100% = 20%

              M2                                       10cm

          (ii) Inactive part of air can be calculated:

                   100% –20% = 80%   //   M3     =>     8   x 100% = 80%

                                                                                                   M2                     10cm

(b)To find the composition of active part of air using heated copper turnings.

Procedure

Clamp a completely packed/filled open ended glass tube with copper turnings. Seal the ends with glass/cotton wool.

Label two graduated syringes as “A” and “B” Push out air from syringe “A”. Pull in air into syringe “B”.

 Attach both syringe “A” and “B” on opposite ends of the glass tube.

Determine and record the volume of air in syringe “B” V1.

Heat the glass tube strongly for about three minutes.

 Push all the air slowly from syringe “B” to syringe “A” as heating continues. Push all the air slowly from syringe “A” back to syringe “B” and repeatedly back and forth.

 After about ten minutes, determine the new volume of air in syringe “B” V2 

     Set up of apparatus

Sample observations

Colour change from brown to black

Volume of air in syringe “B” before heating    V1             = 158.0cm3

Volume of air in syringe “B” after heating       V2         = 127.2cm3

Volume of air in syringe “B” used by copper    V1 – V2 = 30.8cm3

Sample questions

1. What is the purpose of:

(i) glass/cotton wool

To prevent/stop copper turnings from being blown into the syringe/out of the glass tube

(ii) Passing air through the glass tube repeatedly

To ensure all the active part of air is used up

(iii) Passing air through the glass tube slowly

To allow enough time of contact between the active part of and the heated copper turnings

2. State and explain the observations made in the glass tube.

 Colour change from brown to black

Brown copper metal reacts with the active part of air/oxygen to form black copper (II) oxide.

Chemical equation

     Copper +       Oxygen      ->      Copper (II) oxide

      2Cu(s)    +            O2 (g)        ->          2CuO(s)

The reaction reduces the amount/volume of oxygen in syringe “B” leaving the inactive part of air. Copper only react with oxygen when heated.

3. Calculate the % of

(i) Active part of air

% active part of air =     V1 – V2 x 100%       =>  30.8cm3 x 100% = 19.493%

                                          V1                                                       158.0cm3

(ii) Inactive part of air

Method 1

% inactive part of air = V2 x 100%    =>127.2cm3 x 100% = 80.506%

                                                 V1                                       158.0cm3

Method 2

 % inactive part of air = 100% -% active part of air

        => 100 % – 19.493 % = 80.507%

4. The % of active part of air is theoretically higher than the above while % of inactive part of air is theoretically lower than the above. Explain.

 Not all the active part of air reacted with copper

5. State the main gases that constitute:

(a )active part of air.

Oxygen

(b) Inactive part of air

Nitrogen, carbon (IV) oxide and noble gases

6. If the copper turnings are replaced with magnesium shavings the % of active part of air obtained is extraordinary very high. Explain.

Magnesium is more reactive than copper. The reaction is highly exothermic. It generates enough heat for magnesium to react with both oxygen and nitrogen in the air.

A white solid/ash mixture of Magnesium oxide and Magnesium nitride is formed. This considerably reduces the volume of air left after the experiment.

Chemical equation

     Magnesium     +       Oxygen      ->      magnesium (II) oxide

      2Mg(s)              +            O2 (g)        ->          2MgO(s)

    Magnesium       +      Nitrogen    ->      magnesium (II) nitride

      3Mg(s)               +            N2 (g)        ->           Mg3N2 (s)

(c)To find the composition of active part of air using alkaline pyrogallol

Procedure

Measure about 2cm3 of dilute sodium hydroxide into a graduated gas jar. Record the volume of the graduated cylinder V1.

Place about two spatula end full of pyrogallol/1, 2, 3-trihydroxobenzene into the gas jar. Immediately place a cover slip firmly on the mouth of the gas jar. Swirl thoroughly for about two minutes.

Invert the gas jar in a trough/basin containing water. Measure the volume of air in the gas jar V2

Sample observations

Colour of pyrogallol/1, 2, 3-trihydroxobenzene change to brown.

Level of water in gas jar rises when inverted in basin/trough.

Volume of gas jar /air in gas jar V1= 800cm3  

 Volume of gas jar /air in gas jar after shaking with alkaline pyrogallol/1, 2, 3-trihydroxobenzene V2= 640 cm3

   Sample questions

1. Which gas is absorbed by alkaline pyrogallol/1,2,3-trihydroxobenzene

                   Oxygen

2. Calculate the

(i) % of active part of air

V1-V2 x 100%          => (800cm3 – 640 cm3) x 100%     = 20%

                       V1                                     800cm3

(ii) % of inactive part of air

    V2 x 100%             =>     640 cm3 x 100%     = 80%

                       V1                                800cm3

(d)To establish the presence of carbon (IV) oxide in air using lime water Pass tap water slowly into an empty flask as in the set up below

Sample observation questions

  1. What is the purpose of paper cover?

To ensure no air enters into the lime water.

  • What happens when water enters the flask?

 It forces the air from the flask into the lime water.

3. What is observed when the air is bubbled in the lime water?

A white precipitate is formed. The white precipitate dissolves on prolonged bubbling of air.

4. (a) Identify the compound that form:

          (i)lime water

                   Calcium hydroxide / Ca(OH)2

          (ii) White precipitate

                   Calcium carbonate/ CaCO3

                (iii) When the white precipitate dissolves

                   Calcium hydrogen carbonate/ CaHCO3

     (b)Write the chemical equation for the reaction that tale place when:

          (i) White precipitate is formed

          Calcium hydroxide   +   carbon (IV) oxide   -> Calcium carbonate   +   water

      Ca (OH) 2(aq)     +   CO2 (g)     ->   CaCO3(s)   + H2O (l)

(ii) White precipitate dissolves

Calcium carbonate +   water+   carbon (IV) oxide -> Calcium hydrogen carbonate

            CaCO3(s)        + H2O (l) +       CO2 (g) -> CaHCO3 (aq)

5. State the chemical test for the presence of carbon (IV) oxide gas based on 4(a) and (b) above:

Carbon (IV) oxide forms a white precipitate with lime water that dissolves in excess of the gas.

6. State the composition of carbon (IV) oxide gas by volume in the air.

                   About 0.03% by volume

B.OXYGEN

a) Occurrence.

1. Fifty 50% of the earth’s crust consist of Oxygen combined with other elements e.g. oxides of metals

2. About 70% of the earth is water made up of Hydrogen and Oxygen.

3. About 20% by volume of the atmospheric gases is Oxygen that form the active part of air.

b) School laboratory preparation.

Oxygen was first prepared in 1772 by Karl Scheele and later in 1774 by Joseph Priestly. It was Antony Lavoisier who gave it the name “Oxygen”

Procedure

Method 1: Using Hydrogen peroxide

 Half fill a trough/basin with tap water. Place a bee hive shelf/stand into the water.

Completely fill the gas jar with water and invert in onto the bee hive shelf/stand.

Clamp a round bottomed flask and set up the apparatus as below.

Collect several gas jars of Oxygen covering each sample.

Sample observation questions

1. What is observed when the hydrogen peroxide is added into the flask?

          Rapid effervescence/bubbling/fizzing

2. Describe the colour and smell of the gas

          Colourless and odorless

3. (a)Name the method of gas collection used.

          –Over water

          -Upward delivery

          -Down ward displacement of water

   (b)What property of Oxygen makes it to be collected using the method above?

          -Slightly soluble in water

4. What is the purpose of manganese (IV) oxide?

          Manganese (IV) oxide is catalyst.

 A catalyst is a substance that speeds up the rate of a chemical reaction but remain chemically unchanged at the end of the reaction.

Hydrogen peroxide decomposes slowly to form water and Oxygen gas.

 A little Manganese (IV) oxide speeds up the rate of decomposition by reducing the time taken for a given volume of Oxygen to be produced.

  5. Write the equation for the reaction.

          Hydrogen peroxide    ->         Water     +      Oxygen

                   2H2O2 (aq)                -> 2H2O (l)   +        O2 (g)

6. Lower a glowing splint slowly into a gas jar containing Oxygen gas. State what is observed.

The glowing splint relights/rekindles

Oxygen relights/rekindles a glowing splint. This is the confirmatory test for the presence of Oxygen gas 

Method 1: Using Sodium peroxide

 Half fill a trough/basin with tap water. Add four drops of phenolphthalein indicator.

 Place a bee hive shelf/stand into the water.

Completely fill a gas jar with water and invert in onto the bee hive shelf/stand. Clamp a round bottomed flask and set up the apparatus as below

Collect several gas jars of Oxygen covering each sample.

Sample observation questions

1. What is observed when water is added?

(i) Into the flask containing sodium peroxide

          Rapid effervescence/bubbling/fizzing

          (ii) Phenolphththalein

Remains colourless /Phenolphthalein indicator is colourless in neutral solution

2. Describe the colour and smell of the gas

          Colourless and odorless

3.(a)Name the method of gas collection used.

 –Over water. Oxygen is slightly soluble in water.

4. Test the gas by lowering a glowing splint slowly into a gas jar containing the prepared sample.

The glowing splint relights/rekindles. This confirms the presence of Oxygen gas

5. Write the equation for the reaction.

          Sodium peroxide + Water     -> Sodium hydroxide    +      Oxygen

            2Na2O2 (aq)          + 2H2O (l)   -> 4NaOH (aq)       +         O2 (g)

1. Test the gas by lowering a glowing splint slowly into a gas jar containing the prepared sample.

The glowing splint relights/rekindles.

This confirms the presence of Oxygen gas

2. Write the equation for the reaction.

Potassium Chlorate (V)     -> Potassium Chloride   + Oxygen

2KClO3 (aq)                   ->        2KCl (aq)       +         3O2 (g)

3. What is the purpose of manganese (IV) oxide?

Manganese (IV) oxide is catalyst.

 A catalyst is a substance that speeds up the rate of a chemical reaction but remain chemically unchanged at the end of the reaction.

Potassium Chlorate (V) decomposes slowly to form potassium chloride and Oxygen gas.

 A little Manganese (IV) oxide speeds up the rate of decomposition by reducing the time taken for a given volume of Oxygen to be produced.

(c)Uses of Oxygen

1. Oxygen is put in cylinders for use where natural supply is not sufficiently enough. This is mainly in:

          (i)Mountain climbing/Mountaineering-at high altitudes, the concentration of air/oxygen is low. Mountain climbers must therefore carry their own supply of oxygen for breathing.

          (ii) Deep sea diving-Deep sea divers carry their own supply of Oxygen.

(iii) Saving life in hospitals for patients with breathing problems and during anesthesia.

2. A mixture of oxygen and some other gases produces a flame that is very hot.

(i) Oxy-acetylene/ethyne flame is produced when Ethyne/acetylene gas is burnt in pure oxygen. The flame has a temperature of about 3000oC.It is used for welding /cutting metals.

(ii)Oxy-hydrogen flame is produced when Hydrogen is burn in pure oxygen. The flame has a temperature of about 2000oC.It is used also for welding /cutting metals.

3. Oxy-hydrogen mixture is used as rocket fuel

4. A mixture of charcoal, petrol and liquid Oxygen is an explosive.

(d) Chemical properties of Oxygen /combustion.

Oxygen is a very reactive non metal. Many elements react with oxygen through burning to form a group of compounds called Oxides.

 Burning/combustion is the reaction of Oxygen with an element/substances.

Reaction in which a substance is added oxygen is called Oxidation reaction. Burning/combustion are an example of an oxidation reaction.

Most non metals burn in Oxygen/air to form an Oxide which in solution / dissolved in water is acidic in nature. They turn blue litmus red.e.g. Carbon (IV) oxide/CO2, Nitrogen (IV) oxide/ NO2, Sulphur (IV) oxide/ SO2

Some non metals burn in Oxygen/air to form an Oxide which in solution / dissolved in water is neutral in nature. They don’t turn blue or red litmus. E.g. Carbon (II) oxide/CO, Water/ H2O

All metals burns in Oxygen/air to form an Oxide which in solution/dissolved in water is basic/alkaline in nature. They turn red litmus blue.e.g.

Magnesium oxide/MgO, Sodium Oxide/ Na2O, Copper (II) oxide/CuO
Elements/substances burn faster in pure Oxygen than in air

Air contains the inactive part of air that slows the rate of burning of substances/elements.

(i)Reaction of metals with Oxygen/air

The following experiments show the reaction of metals with Oxygen and air.

  I. Burning Magnesium   

Procedure

  (a)Cut a 2cm length piece of magnesium ribbon. Using a pair of tongs introduce it to a Bunsen flame. Remove it when it catches fire. Observe.

Place the products in a beaker containing about 5cm3 of water. Test the solution/mixture using litmus papers

  (b)Cut another 2cm length piece of magnesium ribbon. Using a pair of tongs introduce it to a Bunsen flame. When it catches fire, lower it slowly into a gas jar containing Oxygen.

 Place about 5cm3 of water into the gas jar. Test the solution/mixture using litmus papers. Test the solution/mixture using litmus papers

Observations

(a)In air

Magnesium burns with a bright blindening flame in air forming white solid/ash /powder. Effervescence/bubbles/ fizzing Pungent smell of urine. Blue litmus paper remains blue. Red litmus paper turns blue

(b) In pure Oxygen 

Magnesium burns faster with a very bright blindening flame pure oxygen forming white solid/ash /powder. No effervescence/bubbles/ fizzing. No pungent smell of urine. Blue litmus paper remains blue. Red litmus paper turns blue

Explanation

Magnesium burns in air producing enough heat energy to react with both Oxygen and Nitrogen to form Magnesium Oxide and Magnesium nitride. Both Magnesium Oxide and Magnesium nitride are white solid/ash /powder.

Chemical equations

Magnesium     +      Oxygen      ->      Magnesium Oxide

        2Mg(s)    +          O2(g)      ->             2MgO(s)

Magnesium     +      Nitrogen      ->      Magnesium Nitride

                   3Mg(s)    +          N2(g)      ->             Mg3N2 (s)

Magnesium Oxide dissolves in water to form a basic/alkaline solution of Magnesium hydroxide

Chemical equations

Magnesium Oxide     +      Water         ->      Magnesium hydroxide

                    2Mg(s)            +          O2 (l)      ->             2MgO(s)

Magnesium Nitride dissolves in water to form a basic/alkaline solution of Magnesium hydroxide and producing Ammonia gas. Ammonia is also an alkaline/basic gas that has a pungent smell of urine.

Chemical equations

Magnesium Nitride + Water     ->   Magnesium hydroxide + Ammonia gas

               Mg3N2 (s)          +   6H2O (l)      ->       3Mg (OH)2 (aq)   +     2NH3(g)

II. Burning Sodium   

Procedure

  (a)Carefully cut a very small piece of sodium. Using a deflagrating spoon introduce it to a Bunsen flame. Remove it when it catches fire. Observe.

Place the products in a beaker containing about 20cm3 of water. Test the solution/mixture using litmus papers

  (b) Carefully cut another very small piece of sodium. Using a deflagrating spoon introduce it to a Bunsen flame. When it catches fire, lower it slowly into a gas jar containing Oxygen.

 Place about 20 cm3 of water into the gas jar. Test the solution/mixture using litmus papers. Test the solution/mixture using litmus papers

Observations

(a)In air

Sodium burns with a yellow flame in air forming a black solid. Blue litmus paper remains blue. Red litmus paper turns blue

(b) In pure Oxygen 

Sodium burns faster with a golden yellow flame in pure oxygen forming a yellow solid. Effervescence/bubbles/ fizzing. Gas produced relights glowing splint. Blue litmus paper remains blue. Red litmus paper turns blue.

Explanation

(a)Sodium burns in air forming black Sodium Oxide

  Chemical equations

      Sodium     +      Oxygen/air      ->      Sodium Oxide

        4Na(s)    +          O2 (g)             ->             2Na2O(s)

Sodium Oxide dissolves in water to form a basic/alkaline solution of Sodium hydroxide

Chemical equations

Sodium Oxide     +      Water            ->      Sodium hydroxide

               Na2O(s)          +      H2O (l)          ->             2NaOH (aq)

(b)Sodium burns in pure oxygen forming yellow Sodium peroxide

  Chemical equations

      Sodium     +      Oxygen      ->      Sodium peroxide

        2Na(s)    +          O2 (g)      ->             Na2O2 (s)

Sodium peroxide dissolves in water to form a basic/alkaline solution of Sodium hydroxide. Oxygen is produced.

Chemical equations

Sodium Oxide     +      Water            ->      Sodium hydroxide +   Oxygen

               2Na2O2 (s)       +      2H2O (l)       ->             4NaOH (aq)       +   O2 (l)

III. Burning Calcium

   Procedure

  (a)Using a pair of tongs hold the piece of calcium on a bunsen flame.

Observe.

Place the products in a beaker containing about 2cm3 of water. Test the solution/mixture using litmus papers

  (b)Using a pair of tongs hold another piece of calcium on a Bunsen flame. Quickly lower it into a gas jar containing Oxygen gas .Observe.

Place about 2cm3 of water. Swirl.

Test the solution/mixture using litmus papers

Observations

(a)In air

Calcium burns with difficulty producing a faint red flame in air forming a white solid. Blue litmus paper remains blue. Red litmus paper turns blue

(b) In pure Oxygen 

Calcium burns with difficulty producing a less faint red flame Oxygen forming a white solid. Blue litmus paper remains blue. Red litmus paper turns blue

Explanation

(a)Calcium burns in air forming white calcium Oxide. Calcium Oxide coat/cover the calcium preventing further burning.

  Chemical equations

      Calcium     +      Oxygen/air      ->      calcium Oxide

        2Ca(s)    +          O2(g)             ->             2CaO(s)

Small amount of Calcium Oxide dissolves in water to form a basic/alkaline solution of Calcium hydroxide. The common name of Calcium hydroxide is lime water.

Chemical equations

Calcium Oxide     +      Water            ->      Calcium hydroxide

               CaO(s)          +      H2O (l)          ->             Ca (OH) 2 (aq)

IV. Burning Iron

   Procedure

  (a)Using a pair of tongs hold the piece of Iron wool/steel wire on a Bunsen flame.

Observe.

Place the products in a beaker containing about 2cm3 of water. Test the solution/mixture using litmus papers

  (b)Using a pair of tongs hold another piece of Iron wool/steel wire on a Bunsen flame.

Quickly lower it into a gas jar containing Oxygen gas .Observe.

Place about 2cm3 of water. Swirl. Test the solution/mixture using litmus papers

Observations

(a)In air

Iron wool/steel wire burns producing an Orange flame in air forming a brown solid. Blue litmus paper remains blue. Red litmus paper turns faint blue

(b) In pure Oxygen 

Iron wool/steel wire burns producing a golden Orange flame in Oxygen forming a Brown solid. Blue litmus paper remains blue. Red litmus paper turns faint blue

Explanation

(a)Iron burns in air forming brown Iron (III) Oxide

  Chemical equations

      Iron     +      Oxygen/air      ->      Iron (III) Oxide

   4Fe(s)    +          3O2 (g)             ->             2Fe2O3(s)

Very small amount of Iron (III) Oxide dissolves in water to form a weakly basic/alkaline brown solution of Iron (III) hydroxide.

Chemical equations

Calcium Oxide     +      Water            ->      Iron (III) hydroxide

               Fe2O3(s)          +      3H2O (l)          ->             2Fe (OH) 3 (s)

V. Burning Copper

   Procedure

  (a)Using a pair of tongs hold the piece of copper turnings/shavings on a Bunsen flame.

Observe.

Place the products in a beaker containing about 2cm3 of water. Test the solution/mixture using litmus papers

  (b)Using a pair of tongs hold another piece of Copper turnings/shavings on a Bunsen flame. Quickly lower it into a gas jar containing Oxygen gas .Observe.

Place about 2cm3 of water. Swirl. Test the solution/mixture using litmus papers

Observations

(a)In air

Copper turnings/shavings burns with difficulty producing a green flame in air forming a black solid. Blue litmus paper remains blue. Red litmus paper turns faint blue

(b) In pure Oxygen 

Copper turnings/shavings burns less difficulty producing a green flame in Oxygen forming a Brown solid. Blue litmus paper remains blue. Red litmus paper turns faint blue

Explanation

(a)Copper burns in air forming black Copper (II) Oxide

  Chemical equations

     Copper    +      Oxygen/air       ->      Copper (II) Oxide

     2 Cu(s)    +          O2 (g)             ->             2CuO(s)

Very small amount of Copper (II) Oxide dissolves in water to form a weakly basic/alkaline blue solution of Copper (II) hydroxide.

Chemical equations

Copper (II) Oxide     +      Water    ->      Copper (II) hydroxide

               CuO(s)                +      H2O (l)          ->             Cu (OH) 2 (s)

(i)Reaction of non metals with Oxygen/air

The following experiments show the reaction of non metals with Oxygen and air.

  I. Burning Carbon

 Procedure

  (a)Using a pair of tongs hold a dry piece of charcoal on a Bunsen flame.

Observe.

Place the products in a beaker containing about 2cm3 of water. Test the solution/mixture using litmus papers

  (b)Using a pair of tongs hold another piece of dry charcoal on a Bunsen flame. Quickly lower it into a gas jar containing Oxygen gas .Observe.

Place about 2cm3 of water. Swirl. Test the solution/mixture using litmus papers

Observations

          -Carbon chars then burns with a blue flame     

          -Colourless and odorless gas produced

-Solution formed turn blue litmus paper faint red.

   Red litmus paper remains red.

Explanation

Carbon burns in air and faster in Oxygen with a blue non-sooty/non-smoky flame forming Carbon (IV) oxide gas.

Carbon burns in limited supply of air with a blue non-sooty/non-smoky flame forming Carbon (IV) oxide gas.

Carbon (IV) oxide gas dissolves in water to form weak acidic solution of Carbonic (IV) acid.

Chemical Equation

                Carbon      +      Oxygen         ->        Carbon (IV) oxide

                                (excess air/oxygen)

C(s)       +   O2 (g)      ->         CO2 (g)      (in excess air)

               Carbon      +      Oxygen         ->        Carbon (II) oxide

                                (limited air/oxygen)

2C(s)              +   O2 (g)             ->  2CO (g)     (in limited air)

            Carbon (IV) oxide     +         Water     ->        Carbonic (IV) acid

                    CO2 (g)   +    H2O (l)             ->             H2CO3 (aq) (very weak acid)

II. Burning Sulphur

 Procedure

  (a)Using a deflagrating spoon place sulphur powder on a Bunsen flame.

Observe.

Place the products in a beaker containing about 3cm3 of water. Test the solution/mixture using litmus papers

  (b) Using a deflagrating spoon place sulphur powder on a Bunsen flame. Slowly lower it into a gas jar containing Oxygen gas. Observe.

Place about 5cm3 of water. Swirl. Test the solution/mixture using litmus papers.

Observations

          -Sulphur burns with a blue flame   

          -Gas produced that has pungent choking smell

-Solution formed turn blue litmus paper faint red.

   Red litmus paper remains red.

Explanation

Sulphur burns in air and faster in Oxygen with a blue non-sooty/non-smoky flame forming Sulphur (IV) oxide gas.

Sulphur (IV) oxide gas dissolves in water to form weak acidic solution of Sulphuric (IV) acid.

Chemical Equation

                Sulphur      +      Oxygen         ->        Sulphur (IV) oxide

                   S(s)       +   O2 (g)      ->         SO2 (g)      (in excess air)              

              Sulphur (IV) oxide +          Water     ->        Sulphuric (IV) acid

                    SO2 (g)   +    H2O (l)   ->       H2SO3 (aq) (very weak acid)

III. Burning Phosphorus

 Procedure

  (a)Remove a small piece of phosphorus from water and using a deflagrating spoon (with a lid cover) places it on a Bunsen flame.

Observe.

Carefully put the burning phosphorus to cover gas jar containing about 3cm3 of water. Test the solution/mixture using litmus papers

  (b) Remove another small piece of phosphorus from water and using a deflagrating spoon (with a lid cover) place it on a Bunsen flame.

 Slowly lower it into a gas jar containing Oxygen gas with about 5 cm3 of water. Observe.

Swirl. Test the solution/mixture using litmus papers.

Observations

          -Phosphorus catches fire before heating on Bunsen flame

-Dense white fumes of a gas produced that has pungent choking poisonous smell

-Solution formed turn blue litmus paper faint red.

   Red litmus paper remains red.

Explanation

Phosphorus is stored in water. On exposure to air it instantaneously fumes then catch fire to burn in air and faster in Oxygen with a yellow flame producing dense white acidic fumes of Phosphorus (V) oxide gas.

Phosphoric (V) oxide gas dissolves in water to form weak acidic solution of Phosphoric (V) acid.

Chemical Equation

                Phosphorus    +     Oxygen      ->        Phosphorous (V) oxide

                   4P(s)  +      5O2 (g)        ->     2P2O5(s)                  

              Phosphorous (V) oxide + Water     ->        Phosphoric (V) acid

                   P2O5(s)      +    3H2O (l)          ->      2H3PO4 (aq) (very weak acid)

(e) Reactivity series/competition for combined Oxygen.

The reactivity series is a list of elements/metals according to their affinity for oxygen.

Some metals have higher affinity for Oxygen than others.

 A metal/element with higher affinity for oxygen is placed higher/on top of the one less affinity.

         The complete reactivity series of metals/elements

Most reactive Element/MetalSymbol
PotassiumK
SodiumNa
CalciumCa
MagnesiumMg
AluminumAl
CarbonC
ZincZn
IronFe
TinSn
LeadPb
HydrogenH
CopperCu
MercuryHg
SilverAg
GoldAu
PlatinumLeast reactive Pt

Metals compete for combined Oxygen. A metal/element with higher affinity for oxygen removes Oxygen from a metal lower in the reactivity series/less affinity for Oxygen.

When a metal/element gains/acquire Oxygen, the process is called Oxidation.   

When metal/element donate/lose Oxygen, the process is called Reduction.

An element/metal/compound that undergoes Oxidation is called Reducing agent.

An element/metal/compound that undergoes Reduction is called Oxidizing agent.

A reaction in which both Oxidation and Reduction take place is called a Redox reaction.

Redox reaction between Magnesium and copper (II) Oxide

Procedure

Place about 2g of copper (II) oxide in a crucible with a lid. Place another 2g of Magnesium powder into the crucible. Mix thoroughly.

 Cover the crucible with lid. Heat strongly for five minutes.

 Allow the mixture to cool. Open the lid. Observe.

Observation

Colour change from black to brown. White solid power formed.

Explanation

Magnesium is higher in the reactivity series than Copper. It has therefore higher affinity for Oxygen than copper.

 When a mixture of copper (II) oxide and Magnesium is heated, Magnesium reduces copper (II) oxide to brown copper metal and itself oxidized to Magnesium oxide. Magnesium is the reducing agent because it undergoes oxidation process.

 Copper (II) oxide is the oxidizing agent because it undergoes redox reduction process.

The mixture should be cooled before opening the lid to prevent hot brown copper from being reoxidized back to black copper (II) oxide.

The reaction of Magnesium and Copper (II) oxide is a reaction

Chemical equation

Reduction process
Oxidation process

    1. Copper (II) oxide   +   Magnesium    ->   Magnesium oxide   +   Copper

           (black)                                           (white ash/solid)        (brown)

 CuO(s)          +        Mg(s)        ->          MgO(s)            +      Cu(s)

  (Oxidizing Agent)    (Reducing Agent)

   2. Zinc (II) oxide   +   Magnesium    ->   Magnesium oxide   +   Zinc

      (yellow when hot)                               (white ash/solid)        (grey)

          ZnO(s)         +        Mg(s)        ->          MgO(s)            +      Zn(s)

(Oxidizing agent)    (Reducing agent)

3. Zinc (II) oxide   +   Carbon    ->   Carbon (IV) oxide gas   +   Zinc

      (yellow when hot)                      (colourless gas)            (grey)

          ZnO(s)         +        C(s)        ->          CO2 (g)            +      Zn(s)

(Oxidizing agent)    (Reducing agent)

The reactivity series is used during extraction of metals from their ore. An ore is a rock containing mineral element which can be extracted for commercial purposes. Most metallic ores occur naturally as:

          (i) oxides combined with Oxygen

          (ii) sulphides combined with Sulphur

          (iii) carbonates combined with carbon and Oxygen.                             

Metallic ores that naturally occur as metallic sulphides are first roasted in air to form the corresponding oxide. Sulphur (IV) oxide gas is produced. e.g.

          Copper (I) sulphide   +   Oxygen    ->   Copper (I) Oxide + Sulphur (IV) oxide

Cu2S(s)         +     O2 (g)     ->        2Cu(s)        +       SO2 (g)

          Zinc (II) sulphide      +   Oxygen    ->   Zinc (II) Oxide     +   Sulphur (IV) oxide

                   ZnS(s)          +     O2 (g)     ->        Zn(s)          +       SO2 (g)

          Lead (II) sulphide     +   Oxygen    ->   Lead (II) Oxide    +   Sulphur (IV) oxide

                   PbS(s)          +     O2 (g)     ->        Pb(s)         +       SO2 (g)

          Iron (II) sulphide      +   Oxygen    ->   Iron (II) Oxide     +    Sulphur (IV) oxide

                  FeS(s)           +      O2 (g)     ->        Fe(s)          +       SO2 (g)

Metallic ores that naturally occur as metallic carbonates are first heated in air. They decompose/split to form the corresponding oxide and produce Carbon (IV) oxide gas. .e.g.

     Copper (II) carbonate    ->    Copper (II) oxide   +   Carbon (IV) oxide

          CuCO3(s)    ->   CuO(s)      +       CO2 (g)

     Zinc (II) carbonate    ->    Zinc (II) oxide   +   Carbon (IV) oxide

ZnCO3(s)           ->         ZnO(s)       +          CO2 (g)

     Lead (II) carbonate    ->    Lead (II) oxide   +   Carbon (IV) oxide

PbCO3(s)           ->         PbO(s)       +          CO2 (g)

     Iron (II) carbonate    ->    Iron (II) oxide   +   Carbon (IV) oxide

FeCO3(s)           ->         FeO(s)       +          CO2 (g)

Metallic ores